50=2x^2+16x-32

Solution for 50=2x^2+16x-32 equation:

50=2x^2+16x-32

We move all terms to the left:

50-(2x^2+16x-32)=0

We get rid of parentheses

-2x^2-16x+32+50=0

We add all the numbers together, and all the variables

-2x^2-16x+82=0

a = -2; b = -16; c = +82;
Δ = b2-4ac
Δ = -162-4·(-2)·82
Δ = 912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{912}=\sqrt{16*57}=\sqrt{16}*\sqrt{57}=4\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{57}}{2*-2}=\frac{16-4\sqrt{57}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{57}}{2*-2}=\frac{16+4\sqrt{57}}{-4}
$